# Problems on Trains Aptitude Questions and Answers , Methods shortcut tricksProblems on Trains Aptitude Questions and Answers , Methods shortcut tricks

## Problems on Trains Aptitude Questions and Answers, Methods shortcut tricks

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Takshila Learning regularly offers you different blogs and articles on important topics, news, and information related to banking exams. In this article, the following topic ’Problem on Trains’ from the Quantitative section has been explained.

## Problems on trains

Problems on trains are similar to ‘Time and Distance’ problems. The only difference here is that we have to consider the length of the train as distance while solving problems on trains.

Some important points:

• To convert ‘x’ Km/hr into m/s

–  Multiply x with 5/18

• To convert ‘y’ m/s into km/hr

–  Multiply y with 18/5

• Distance covered by a train of length L meters while passing a stationary pole is equal to the length of the train.
• Distance covered by a train of length L meters while passing a stationary object of length P meters is equal to the length of the train & length of the stationary object (L + P) meters.
• If two trains are moving in the opposite direction to each other and their speeds are x km/h and y km/h then their relative speed is equal to (x + y) km/h.
• If two trains are moving in the same direction to each other and their speeds are x km/h and y km/h (x > y) then their relative speed is equal to (x –y) km/h.

## Let us look at some problems – Problems on trains

Ex: A train of length of 180 meters is moving with a speed of 54 km/hr. Find out the time taken by it to cross a stationary pole?

1. 12 s          b. 10 s           c. 16 s           d. 20 s              e. None of these

Sol: Sol: = 180/(54*5/18) = 20 sec

Ans: (d)

Ex: A train of length 240 m speed is moving with the speed of 36 Km/hr. Find out the time taken by it to cross a platform of length 160 m?

1. 40 s            b. 35 s             c. 38 s            d. 42 s            e. None of these

Sol: [240+160]/ (36*5/18) = 40 sec

Ans: (a)

Ex: Two trains of length 360 and 140 meters are moving in the same direction with the speed of 54 m/s and 44 m/s. How much time taken will the faster train take to overcome the slower train?

1. 50 s                b. 52 s                c. 48 s             d. 18 s                 e. None of these

Sol: = (360+140)/ (54-44) = 50 sec

Ans: (a)

Ex: A train passes a stationary man standing on the platform in 7 seconds and passes the platform completely in 28 seconds. If the length of the platform is 330 meters, then find what is the length of the train?

1. 100m                  b. 110m             c. 130m               d. 170m            e. None of these

Sol: Let the length of the train be x mtrs.

As the speed of the train will be equal in both the cases:

So, x / 7 = (x + 330) / 28

Hence, x= 110 mtrs

Ans: (b)

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