## Percentage Practice Problems for IBPS/SBI/RRB POs and Clerks

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## Percentage Practice Problems

**Q: 1 A space research company wants to sell its two machines A and B. If the machine A is sold at 20%loss and the machine B at 30% gain, the company will not lose anything. If the machine A is sold at 15% loss and the machine B at 15% gain, the company will lose Rs. 6 million in the deal. What is the cost of machine B?**

(1) Rs. 140 million (2) Rs. 130 million (3) Rs. 110 million (4) Rs. 80 million (5) None of these

Sol: Let the S.P of A and B ‘x’ and ‘y’ respectively.

Given that

0.2x = 0.3y

2x = 3y … (i)

Also,

0.15x – 0.15y = Rs. 6 million

x – y = Rs. 600 million … (ii)

Solving equation (i) and (ii), we get

y = **Rs. 80 million**.

Hence, the correct answer is option (4).

**Q: 2 The profit by selling an item was 25%. If the item was marked 40% above the selling price then whatis the ratio of the marked price to the cost price of the item?**

(1) 4/5 (2) 7/4 (3) 6/5 (4) 8/5 (5) None of these

Sol: Let the C.P of the article be 100Rs

So, S.P = 125Rs

Now, M.P = 175Rs

So, required ratio = MP/CP = 175/100 = 7/4

Hence, the correct answer is option (2).

**Q: 3 The price of a watch was first increased by 20% and later on the price was decreased by 25% due to reduction in sales. Find the net percentage change in final price of Watch.**

(1) 20% (2) 25% (3) 40% (4) 10% (5) None of these

Sol: Let the initial price of the watch = **100Rs**

After the increase, price of the watch = 120Rs

Later on, price of the watch was decreased by 25%

Therefore, its price = **90Rs**

Net change in the price = 10Rs

So, Net Percentage change = **10%**** **

Hence, the correct answer is option (4).

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**Q: 4 A profit of 8% is made by selling a jean after giving a discount of 12%. If the marked price of the shirt is Rs.1080, find its cost price.**

(1) 860 (2) 760 (3) 880 (4) 950 (5) None of these

Sol: Marked Price = Rs.1080

After giving 12% discount on M.P, S.P of the jean = 950.4 Rs

C.P of the jean = 108 % of x = 950.4

= **880 Rs**

Hence, the correct answer is option (3).

**Q: 5 A mixture of milk and water measures 60 litres which contains 10% water. How much water should be added to it so that water makes 25% in the new mixture?**

(1) 12 litres (2) 15 litres (3) 17 litres(4) 9 litres (5) None of these

Sol: Total mixture = 60 litres

Water in the mixture = 6 litres

So, Milk = 54 litres

6 + x = 25% of (60 + x)

6 + x = of (60 + x)

6 + x = 15 +

So, x = **12 Litres**

Hence, the correct answer is option (1).

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