# FREE & ONLINE QUANT QUIZ FOR SBI CLERK EXAMS 2019 : PART – 38 ## FREE & ONLINE QUANT QUIZ FOR SBI CLERK EXAMS 2019

This quiz contains 5 questions based on mathematical puzzle, 5 questions on simplification and 5 questions on quadratic equations. Try to solve this quiz in as less time as possible because time and accuracy is the key factor to crack any competitive exam.

Directions (1-5): There are total five departments in a company. There are total 90 employees in Finance department which is 25% of total employees in the company. 2 / 9 of the total employees of the company are working in HR department. Employees working in Sales department are 25% more than that in HR department. Ratio between employees working in Security and Housing department is 4: 5.

Q1. Find number of employees working in HR department is what percent more than number of employees working in Security department?

(a) 230%

(b) 200%

(c) 120%

(d) 100%

(e) 80%

Q2. Find the average number of employees working in Sales, Finance and Housing department?

(a) 50

(b) 75

(c) 80

(d) 85

(e) 100

Q3. Number of employees in Housing department is how much more than number of employees in Security department?

(a) 10

(b) 15

(c) 18

(d) 20

(e) 25

Q4. In Security department, 40% are female employees then find total male employees working in Security department?

(a) 18

(b) 36

(c) 32

(d) 28

(e) 24

Q5. Ratio between total number of male and female employees in HR department is 2: 3. Find total number of female employees working in HR department?

(a) 42

(b) 48

(c) 54

(d) 60

(e) 66

Directions (6-10): Simplification based Set:

Q6. ?? = ?? + ?? − ??

(a) 5

(b) 7

(c) 8

(d) 10

(e) 12

Q7. ?? × ? +? × ? = ?? × ?

(a) 5

(b) 7

(c) 9

(d) 12

(e) 15

Q8. ??% ?? ? = ??% ?? ??? + ??% ?? ???

(a) 500

(b) 560

(c) 600

(d) 620

(e) 700

Q9. ??? + ?? = ? +??

(a) 90

(b) 100

(c) 120

(d) 140

(e) 160

Q10. ??? / ? = ?? × ? − ??

(a) 12

(b) 15

(c) 16

(d) 7

(e) 8

Directions (11-15): In each of the following questions two equations are given followed by 5 options. You have to solve the equations and give answer:

1. 11 I. 17x² + 48x = 9
II. 13y² = 32y – 12

(a) if x < y
(b) if x ≤ y
(c) relationship between x and y cannot be determined
(d) if x ≥ y
(e) if x > y

1. 12 I. 8x² + 26x + 15 = 0

II. 4y² + 24y + 35 = 0

(a) if x < y
(b) if x ≤ y
(c) relationship between x and y cannot be determined
(d) if x ≥ y
(e) if x > y

1. 13 I. 6x² + 19x + 15 = 0

II. 24y² + 11y + 1 = 0

(a) if x < y
(b) if x ≤ y
(c) relationship between x and y cannot be determined
(d) if x ≥ y
(e) if x > y

1. 14 I. 2x² + 11x + 15 = 0

II. 4y² + 22y + 24 = 0

(a) if x < y
(b) if x ≤ y
(c) relationship between x and y cannot be determined
(d) if x ≥ y
(e) if x > y

1. 15 I. 2x² + 9x + 9 = 0
II. 2y² + 17y + 36 = 0

(a) if x < y
(b) if x ≤ y
(c) relationship between x and y cannot be determined
(d) if x ≥ y
(e) if x > y

Solutions: (1-10)

S1. Ans. (d)

Sol. Required % = (80 – 40) / 40 × 100 = 100%

S2. Ans. (c)

Sol. Required average = (100 + 90 + 50) / 3 = 240 / 3 = 80

S3. Ans. (a)

Sol. Required difference = 50 − 40 = 10

S4. Ans. (e)

Sol. Total number of male employees working in Security department = (60 / 100) × 40 = 24

S5. Ans. (b)

Sol. Total number of female employees working in HR department = (3 / 5) × 80 = 48

S6. Ans. (b)

S7. Ans. (d)

S8. Ans. (a)

S9. Ans. (c)

S10. Ans. (e)

S11. Ans.(a)
Sol.
I. 17x² + 48x – 9 = 0
⇒ 17x² + 51x – 3x – 9 = 0
⇒ (x + 3) (17x – 3) = 0
⇒ x = 3/17, – 3

II. 13y² – 32y + 12 = 0
⇒ 13y² – 26y – 6y + 12 = 0
⇒ (y – 2) (13y – 6) = 0
⇒ y = 2, 6/13
y > x

S12. Ans.(d)
Sol.
I. 8x² + 26x + 15 = 0
⇒ 8x² + 20x + 6x + 15 = 0
⇒ 4x (2x + 5) + 3(2x + 5) = 0
⇒ (2x + 5) (4x + 3) = 0
⇒ x = – 5/2, –3/4

II. 4y² + 24y + 35 = 0
⇒ 4y² + 10y + 14y + 35 = 0
⇒ 2y (2y + 5) + 7 (2y + 5) = 0
⇒ (2y + 5) (2y + 7) = 0
⇒ y = –5/2, –7/2
x ≥ y

S13. Ans.(a)
Sol.
I. 6x² + 19x + 15 = 0
⇒ 6x² + 9x + 10x + 15 = 0
⇒ (2x + 3) (3x + 5) = 0
⇒ x = –3/2, –5/3

II. 24y² + 11y + 1 = 0
⇒ 24y² + 8y + 3y + 1= 0
⇒ (3y + 1) (8y + 1) = 0
⇒ y = –1/3, –1/8
y > x

S14. Ans.(c)
Sol.
I. 2x² + 11x + 15 = 0
⇒ 2x² + 6x + 5x + 15 = 0
⇒ (x + 3) (2x + 5) = 0
⇒ x = – 3, –5/2

II. 4y² + 22y + 24 = 0
⇒ 2y² + 11y + 12 = 0
⇒ 2y² + 8y + 3y + 12 = 0
⇒ (y + 4) (2y + 3) = 0
⇒ y = –4, –3/2
No relation

S15. Ans.(e)
Sol.
I. 2x² + 9x + 9 = 0
⇒ 2x² + 6x + 3x + 9 = 0
⇒ (x + 3) (2x + 3) = 0
⇒ x = –3, –3/2

II. 2y² + 17y + 36 = 0
⇒ 2y² + 8y + 9y + 36 = 0
⇒ (y + 4) (2y + 9) = 0
y = – 4, –9/2
x > y

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April 27, 2019

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