# NCERT Solution For Class 7 Maths – Practical Geometry

## NCERT Solutions for Class 7 Maths

NCERT Solutions is known as an extremely helpful resource for preparing for the exam. Takshila Learning provides its learners with access to a wealth of NCERT problems and their solutions. CBSE Class 7 Science NCERT Solutions are built by subject matter experts, so be sure to train learners for a good grade. The questions set out in the NCERT

NCERT Solution For Class 7 Maths – Integers provides us with all-inclusive information on all concepts. As students would have to learn the basics about the subject in class 7, this curriculum for class 7 is comprehensive study material, which explains the concepts in a great way.

## Questions Covered :

Question 1 : Draw a line, say AB, take a point C outside it. Through C, draw a line parallel to AB using ruler and compasses only.

Question 2 : Draw a line l. Draw a perpendicular to l at any point on l. On this perpendicular choose a point X, 4 cm away from l. Through X, draw a line m parallel to l.

Question 3 : Let l be a line and P be a point not on l. Through P, draw a line m parallel to l. Now join P to any point Q on l. Choose any other point R on m. Through R, draw a line parallel to PQ. Let this meet l at S. What shape do the two sets of parallel lines enclose?

Question 4 : Construct ∆XYZ in which XY = 4.5 cm, YZ = 5 cm and ZX = 6 cm.

Question 5 : Construct an equilateral triangle of side 5.5 cm. Solution: Steps of construction:
(i) Draw BC = 5.5 cm.
(ii) Draw two arcs with centres B and C and same radius of 5.5 cm to meet each other at A.
(iii) Join AB and AC.
(iv) ABC is the required triangle.

Question 6 : Draw ∆PQR with PQ = 4 cm, QR = 3.5 cm and PR = 4 cm. What type of triangle is this?

Question 7 : Construct ∆ABC such that AB = 2.5 cm, BC = 6 cm and AC = 6.5 cm. Measure ∠B.

Question 8 : Construct ∆DEF such that DE = 5 cm, DF = 3 cm and m ∠DEF = 90°.

Question 9 : Construct an isosceles triangle in which the lengths of each of its equal sides is 6.5 cm and the angle between them is 110°.

Question 10 : Construct ∆ABC with BC = 7.5 cm, AC = 5 cm and m ∠C = 60°.

Question 11 : Construct ∆ABC, given m ∠A = 60°, m ∠B = 30° and AB = 5.8 cm.

Question 12 : Construct ∆PQR if PQ = 5 cm, m ∠PQR = 105° and m∠QRP = 40°.
(Hint: Recall angle-sum property of a triangle)

Question 13 : Examine whether you can construct ∆DEF such that EF = 7.2 cm, m∠E = 110° and m∠F = 80°. Justify your answer.

Question 14 : Construct the right angled ∆PQR, where m∠Q = 90°, QR = 8 cm and PR = 10 cm.

Question 15 : Construct a right-angled triangle whose hypotenuse is 6 cm long and one of the legs is 4 cm long.

Question 16 : Construct an isosceles right-angled triangle ABC, where m∠ACB = 90° and AC = 6 cm.

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### NCERT Solutions For Class 7 Maths

NCERT Solutions for Class 7 Maths Chapter 1

NCERT Solutions for Class 7 Maths Chapter 2

NCERT Solutions for Class 7 Maths Chapter 3

NCERT Solutions for Class 7 Maths Chapter 4

NCERT Solutions for Class 7 Maths Chapter 5

NCERT Solutions for Class 7 Maths Chapter 6

NCERT Solutions for Class 7 Maths Chapter 7

NCERT Solutions for Class 7 Maths Chapter 8

NCERT Solutions for Class 7 Maths Chapter 9

### NCERT Solutions For Class 7 Maths

NCERT Solutions for Class 7 Maths Chapter 10

NCERT Solutions for Class 7 Maths Chapter 11

NCERT Solutions for Class 7 Maths Chapter 12

NCERT Solutions for Class 7 Maths Chapter 13

NCERT Solutions for Class 7 Maths Chapter 14

NCERT Solutions for Class 7 Maths Chapter 15

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for CBSE/ICSE Live Tuition Class/Animated Video Class
Fill the form for more details.

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