Data Interpretation, DI Questions for IBPS PO & CLERK

Data Interpretation, DI Questions for IBPS PO & CLERK

Data Interpretation is an important topic for all banking & insurance exams as 10-15 questions are asked from this topic in the Preliminary examination & also there is a separate section of Data Interpretation in the Main examination of PO level exams. So, you can understand the importance of this topic. So, we at Takshila Learning are providing you 2 DI sets of Pre-level that will help you crack the exam.

Directions for Questions 1 to 4 : Use the following information to answer the questions given below.

 State Population (.000) Area (1000 sq.km) 1 2500 35 2 3625 47 3 1725 28 4 6600 75 5 4213 42 6 2245 19 7 1675 25

1. The state with the highest population density is:

(1) 1     (2) 4     (3) 5     (4) 6

1. The state with the lowest population density is:

(1) 1     (2) 4     (3) 3     (4) 5

1. For the seven states, the average population density is:

(1) 72   (2) 78   (3) 83   (4) 85

1. The average population of the seven states (in .000s) is:

(1) 3700           (2) 3225           (3) 4150           (4) 3400

Sol 1-4:

1. Formula to calculate population density is

Population density = Population / Area

State 1 Population density = 2500/35 = 71.42

State 4 Population density = 6600/75 = 88

State 5 Population density = 4213/42 = 100.4

State 6 Population density = 2245/19 = 118.4.

Thus, we can say that State 6 has the highest population density.

1. State 3 has the lowest population density of 61.61 than others states [State 1 = 71.42, State 4 = 88, State 5 = 100.4]

1. Total population = 22583and Total area = 271.

So, Average population density = 22583 / 271 = 83 (approx.)

1. Average population of the seven states = Total. Population / 7 = 22583 / 7 = 3226(approx.) So, the nearest answer is 3225.

For the practice of more Data Interpretation sets of PO/Clerk level, click online bank coaching classes.

Directions for Questions 5 to 8: Use the following information given below to answer the questions:

 Plant Polyethylene Naphtha BoPP 1 753 1623 385 2 815 840 700 3 650 1000 650

Production data of various Petrochemical products at three different plants:

1. The total production of all the three products was maximum for which plant, and what was the total production?

(1) Plant 1, 2761         (2) Plant 2, 2385         (3) Plant 1, 2561         (4) Plant 3, 2861

1. The ratio of Polyethylene production to that of BoPP for plant 2 is:

(1) 1.12: 1        (2) 1.22: 1        (3) 1.16: 1       (4) 1.28: 1

1. The total BoPP production for all 3 plants is:

(1) 1635           (2) 1735           (3) 1935          (4) 1755

1. The ratio of Naphtha production to that of BoPP production for plant 1 is:

(1) 4.16: 1        (2) 4.34: 1        (3) 4.26: 1       (4) 4.22: 1

Sol: 5-8:

1. Total production of Plant 1 = 753 + 385 + 1623 = 2761

Total production of Plant 2 = 815 + 700 + 840 = 2355.

Total production of Plant 3 = 650 + 650 + 1000 = 2300.

Hence, the maximum total production of all the three products = 2761 of Plant 1.

1. Polyethylene / BoPP for plant 2 = 815/700 = 1.16.

1. Total BoPP production for all 3 plants per month = 385 + 700 + 650 = 1735

1. For Plant 1 = Naphtha / BoPP=1623 / 385 = 4.22(approx.)

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December 20, 2017